-2x^2-18x+7=0

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Solution for -2x^2-18x+7=0 equation:



-2x^2-18x+7=0
a = -2; b = -18; c = +7;
Δ = b2-4ac
Δ = -182-4·(-2)·7
Δ = 380
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{380}=\sqrt{4*95}=\sqrt{4}*\sqrt{95}=2\sqrt{95}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{95}}{2*-2}=\frac{18-2\sqrt{95}}{-4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{95}}{2*-2}=\frac{18+2\sqrt{95}}{-4} $

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